CODEWITHSUNDEEP
javaandroidlistviewandroid-listview
Oluleye IResþekt Idowu
Oluleye IResþekt Idowu

Reputation: 367

Getting item position in ListView then use the if / else clause or switch statement

I have a listView, I'm wondering how to get the position of the item selected in the ListView so that I can use this code under the OnItemClick method.

string selected = listView.getItemPosition().toString()

So then I can use the if / else clause or switch to say:

if (selected.positionEquals("0")) {
        Intent i = new Intent(this, WebViewActivity.class);
        i.putExtra("keyHTML", "file:///android_asset/page1.html");
        startActivity(i);

I hope I made sense, please note, the listView.getItemPosition().toString() and selected.positionEquals was something I made up so you can get an idea of what I want.

Thanks!

EDIT

I just saw this from another question, I searched before asking this, but this just popped out. Do you think it will work in my case?

listView.setOnItemClickListener(new OnItemClickListener() {
    public void onItemClick(AdapterView<?> parent, View view,
        int position, long id) {

if(position == 1)
{

     Intent myIntent = new Intent(YourActivity.this, SecondActivity.class);
         startActivityForResult(myIntent, 0);
}

if(position == 2)
{

     Intent myIntent =  new Intent(YourActivity.this, ThirdActivity.class);
         startActivityForResult(myIntent, 0);
}
    }
  });

Upvotes: 1

Views: 5158

Answers (5)

Ankitkumar Makwana
Ankitkumar Makwana

Reputation: 3485

yes working for you this way

    listView.setOnItemClickListener(new OnItemClickListener() {
    public void onItemClick(AdapterView<?> parent, View view, int position, long id) {

    if(position == 1)
    {

         Intent myIntent = new Intent(YourActivity.this, SecondActivity.class);
         startActivityForResult(myIntent, position);
    }

    if(position == 2)
    {

         Intent myIntent =  new Intent(YourActivity.this, ThirdActivity.class);
             startActivityForResult(myIntent, position);
    }

 }    
 });

Also switch to will work for you, and if you want compare using String like

string selected = listView.getItemPosition().toString()

then do like

 if (selected.equalsIgnoreCase("0")){

  // do work here 

   }else if(selected.equalsIgnoreCase("1")){

      // do work here 
  }

end so on.

Upvotes: 0

Mitul Gedeeya
Mitul Gedeeya

Reputation: 896

Using Below code Toast has print the position of selected item :- 

listView.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
Toast.makeText(getApplicationContext(),"Position of Selected Item is :-"+position,Toast.LENGTH_LONG).show(); 
}
});

Upvotes: 0

Rahul Gupta
Rahul Gupta

Reputation: 5295

please see the code below :- 

listView.setOnItemClickListener(new OnItemClickListener() {

            @Override
            public void onItemClick(AdapterView<?> arg0, View arg1, int index,
                    long arg3) {
                if (index == 0)) {
        Intent i = new Intent(this, WebViewActivity.class);
        i.putExtra("keyHTML", "file:///android_asset/page1.html");
        startActivity(i);
            }
        });

Upvotes: 0

android_dev
android_dev

Reputation: 1477

Try this code:

    listview.setOnItemClickListener(new OnItemClickListener() {

        @Override
        public void onItemClick(AdapterView<?> arg0, View arg1, int position,
                long arg3) {
            // TODO Auto-generated method stub

        }
    });

here "int position" will gives the selected item index value.

Upvotes: 0

Coderji
Coderji

Reputation: 7745

in one of the parameter of onItemClick there is a position value (third argument) of the clicked item. you dont need to get it progromatically, just use that value to know 

public void onItemClick(AdapterView<?> arg0, View v, int position, long arg3) { //check third argument it automatically get the selected item POSITION
    // TODO Auto-generated method stub
    Intent i;
    switch (position)
    {
    case 0: // first one of the list
        i = new Intent(this, anActivity.class);
        startActivity(i);
        break;
    case 1: // second one of the list.
        i = new Intent(this, anActivity2.class);
        startActivity(i);
        break;
       // and so on...
    }

}

Upvotes: 3

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