CODEWITHSUNDEEP
pythonfunctionspacepunctuation
Sergio
Sergio

Reputation: 43

Python - Remove whitespaces and punctuation without functions

first of all, sorry for my bad english. I'm a beginner programmer and I have some problems with my python program. I have to make a program that normalizes the whitespaces and the punctuation, for example:

If I put a string called 

"   hello   how,   are  u?   "

The new string has to be...

"Hello how are u"

But in my code, the result appears like this and I dont know why:

 "helloo how,, aree u??"

Note: I can't use any kind of function like split(), strip(), etc...

Here is my code:

from string import punctuation

print("Introduce your string: ")
string = input() + " "
word = ""
new_word = ""
final_string = ""

#This is the main code for the program
for i in range(0, len(string)):
    if (string[i] != " " and (string[i+1] != " " or string[i+1] != punctuation)):
        word += string[i]
    if (string[i] != " " and (string[i+1] == " " or string[i+1] == punctuation)):
        word += string[i] + " "
        new_word += word
        word = ""

#This destroys the last whitespace
for j in range(0,len(new_word)-1):
    final_string += new_word[j]

print(final_string)

Thank you all.

EDIT:

Now i have this code:

letter = False

for element in my_string:
    if (element != " " and element != punctuation):
        letter= True
        word += element


print(word)

But now, the problem is that my program doesn't recognize the punctuation so if i put:

"Hello   ... how  are u?"

It has to be like "Hellohowareu"

But it is like:

"Hello...howareu?

Upvotes: 0

Views: 1398

Answers (3)

Dima Tisnek
Dima Tisnek

Reputation: 11781

Now this looks a lot like homework, so here's my stream processing solution, if you can explain this to your teacher, I doubt they'd mind you didn't really do it yourself 😼

def filter(inp):
    for i in inp:
        yield " " if i in " ,.?!;:" else i

def expand(inp):
    for i in inp:
        yield None if i == " " else object(), i

def uniq(inp):
    last = object()
    for key, i in inp:
        if key == last:
            continue
        yield key, i

def compact(inp):
    for key, i in inp:
        yield i

normalised = compact(uniq(expand(filter(input()))))

Upvotes: 0

Dylan Lawrence
Dylan Lawrence

Reputation: 1533

Ok, so first off, you don't need to loop over a range, strings in python are iterable. For example:

my_string = 'How are you?'

for char in my_string:
  #do something each character

Secondly, you're using a very spotty methodology for what you want to remove. It seems your method for catching spaces that occur after a character causes a double append of the last character. I would use a different method much more heavily centered on where you are, not what's in front of you.

Upvotes: 0

Daniel Roseman
Daniel Roseman

Reputation: 599620

I'm not going to write the code for you since this is obviously homework, but I will give you some hints.

I think your approach of checking the next character is a bit error-prone. Rather, I would have a flag that you set when you see a space or punctuation. The next time through the loop, check if the flag is set: if it is, and you still see a space, then ignore it, otherwise, reset the flag to false.

Upvotes: 3

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