Reputation: 43
I have two tables: songs and groups
i want limit the songs are match the group to 3
i tried this:
SELECT
groups.`IDgroup`,
groups.`name` AS g_name,
songs.`IDsong`,
songs.`name` AS s_name
FROM `groups`
LEFT OUTER JOIN songs ON (groups.`IDgroup` = songs.`IDgroup` LIMIT 3)
Upvotes: 2
Views: 337
Reputation: 21532
This query will return the last 3 songs for each group:
SELECT
c.`IDgroup`,
c.`name` AS g_name,
s.`IDsong`,
s.`name` AS s_name
FROM
groups c
JOIN (
SELECT
IF(@C != c.IDgroup, @ROWNUM := 1, @ROWNUM := @ROWNUM +1) AS RN,
@C := c.IDgroup,
c.IDgroup,
s.IDsong,
s.name
FROM groups c
LEFT JOIN songs s ON c.`IDgroup` = s.`IDgroup`
CROSS JOIN (SELECT @C := '') t2
ORDER BY c.IDgroup ASC
) s ON c.`IDgroup` = s.`IDgroup`
JOIN JOIN (
SELECT IDgroup, MAX(rn) AS mx
FROM (
SELECT
IF(@C != c.IDgroup, @ROWNUM := 1, @ROWNUM := @ROWNUM +1) AS rn,
@C := c.IDgroup,
c.IDgroup
FROM groups c
LEFT JOIN songs s ON c.`IDgroup` = s.`IDgroup`
CROSS JOIN (SELECT @C := '') t2
ORDER BY c.IDgroup ASC
) t
GROUP BY IDgroup
) maxsong ON maxsong.IDgroup = c.IDgroup AND s.rn BETWEEN maxsong.mx-2 AND maxsong.mx
ORDER BY c.IDgroup ASC, s.`name` ASC
Fiddle: http://sqlfiddle.com/#!2/b65c3b/1
Upvotes: 1
Reputation: 38
SELECT
g.`IDgroup`,
g.`name` AS g_name,
s.`IDsong`,
s.`name` AS s_name
FROM `groups` g
LEFT OUTER JOIN songs s
using ('idgroup')
LIMIT 3
Upvotes: 1
Reputation: 973
It is generally not a good idea to put a limit on a query that does not explicitly order its results. The reason is that it could return different results over time.
So, you may want to consider adding an
ORDER BY groups.IDgroup
, songs.IDsong
to your query (before the LIMIT 3), assuming that this combination is unique.
Upvotes: 1
Reputation: 5402
Put the limit
out of parentheses:
SELECT
groups.`IDgroup`,
groups.`name` AS g_name,
songs.`IDsong`,
songs.`name` AS s_name
FROM `groups`
LEFT OUTER JOIN songs
ON groups.`IDgroup` = songs.`IDgroup`
LIMIT 3
Upvotes: 1
Reputation: 44831
Take the LIMIT out of the parentheses:
SELECT
groups.`IDgroup`,
groups.`name` AS g_name,
songs.`IDsong`,
songs.`name` AS s_name
FROM `groups`
LEFT OUTER JOIN songs USING (`IDgroup`)
LIMIT 3
Upvotes: 0