CODEWITHSUNDEEP
.netregex
Andy McG
Andy McG

Reputation:

How do I write a .Net Regular Expression to match from the end of line back

I have the following line of text

Reference=*\G{7B35DDAC-FFE2-4435-8A15-CF5C70F23459}#1.0#0#..\..\..\bin\App Components\AcmeFormEngine.dll#ACME Form Engine

and wish to grab the following as two separate capture groups:

AcmeFormEngine.dll
ACME Form Engine

Can anyone help?

Upvotes: 0

Views: 587

Answers (4)

Gishu
Gishu

Reputation: 136613

I voted for tomalask's non-regex approach. However if you HAD to do it with regex, I think you need something like this

\\([^\\/?"<>|]+?)\#([^\\/?"<>|]+?)[\r\n]*$

This will allow things like - and _ which are valid in filenames, Its 2 identical groups (each excluding invalid chars for win32 filenames) beginning with a slash, delimited by a # and at the end of the line (the $). Assuming second group is also a valid win32 filename.. I saw some ugly boxes in the matched second group, the [\r\n]* keeps them away.

e.g. F5C70F23459}#1.0#0#..\..\..\bin\App Components\Acme_Form-Engine.dll#ACME Form Engine
group#1 => Acme_Form-Engine.dll
group#2 => ACME Form Engine

In short this is arcane.. avoid if possible.

Upvotes: 1

Matthew Scharley
Matthew Scharley

Reputation: 132274

Regex r = new Regex("\\(.+?)\#(.+?)$");

Non-greedy multiplicities are great.

'$': Match the end of the string.

"\#(.+?)": Match everything back from the end of the string till the first '#' character and return that in a capture.

"\\(.+?)": Same again, except with an escaped '\'.

Upvotes: 1

Tomalak
Tomalak

Reputation: 338208

If you are sincere of the string format, you can also solve that in an earthbound manner, without regex: Take everything after the last index of '\', and split that at '#'.

Upvotes: 5

Bartek Szabat
Bartek Szabat

Reputation: 3014

    using System.Text.RegularExpressions;

    Regex regex = new Regex(
    @"\\(?<filename>[\w\.]+)\#(?<comment>[\w ]+)$",
    RegexOptions.IgnoreCase
    | RegexOptions.Compiled
    );

Upvotes: 1

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