Reputation: 5381
I'm using camel to route from SOAP web service to Rest Service. My route is like following.
SOAP Service --> Processor A --> Rest --> Processor B .
I'm using Exchange pattern and Rest is hosted in Jboss Server. My problem is how to get Rest Response ( json string ). When i get in message in Processor B it contains the output message or processor A.
<camelContext xmlns="http://camel.apache.org/schema/spring" trace="true">
<route>
<from uri="cxf:bean:serviceA"/>
<process ref="processorA" />
<to uri="cxfrs:bean:serviceRest"/>
<process ref="processorB"/>
</route>
</camelContxt>
I'm new to camel. any help would be appreciated.
Upvotes: 0
Views: 1845
Reputation: 5381
Finally found the answer with the help of friends. It was error in fasterxml jason provider. I changed the json provider to codehaus
<cxf:rsClient id="serviceRest" address="http://localhost:8080/rest-test/rest"
serviceClass="org.apache.cxf.jaxrs.client.WebClient" loggingFeatureEnabled="true" >
<cxf:providers>
<ref bean="jasonProvider"/>
</cxf:providers>
</cxf:rsClient>
<bean id="jasonProvider" class="org.codehaus.jackson.jaxrs.JacksonJsonProvider" />
Now i have the json response in exchange.
Upvotes: 0
Reputation: 3291
You should be able to the REST response in the proxessorB by referencing the exchange in message.
Upvotes: 1