CODEWITHSUNDEEP
phparraysfiltering
Austin
Austin

Reputation: 1627

Split flat array into two arrays based on value

I have a PHP array that I am trying to split into 2 different arrays. I am trying to pull out any values that contain the word "hidden". So one array would contain all the values that do not contain the word "hidden". The other array would contain all the values that do contain the word "hidden". I just can't figure out how to do it though.

The original array is coming from a form post that contains keys and values from a bunch of check boxes and hidden inputs. so the actual post value looks something like this:

Group1 => Array([0] => item1,[1] => item2hidden,[2] => item3,[3] => item4,[4] => item5hidden)

so to simplify it:

$myArray = Array(item1, item2hidden, item3, item4, item5hidden)

final output

$arr1 = (item1, item3, item4)
$arr2 = (item2hidden, item5hidden)

Anyone know how to do something like this?

Upvotes: 19

Views: 41322

Answers (5)

Glavić
Glavić

Reputation: 43552

You can use array_filter() function:

$myArray = array('item1', 'item2hidden', 'item3', 'item4', 'item5hidden');

$arr1 = array_filter($myArray, function($v) { return strpos($v, 'hidden') === false; });
$arr2 = array_diff($myArray, $arr1);

Upvotes: 30

fresbeeplayer
fresbeeplayer

Reputation: 103

Maybe it's just me, but I would go for the clarity of regular expressions...

foreach($myArray as $item) {
    if (preg_match("/hidden$/i", $item)) {
        array_push($arr2, $item);
    } else {
        array_push($arr1, $item);
    }
}

Upvotes: 0

Nikolay Krasnov
Nikolay Krasnov

Reputation: 373

You can use array_filter:

function filtreHiddens($e) {
    if (isset($e['hidden']) && $e['hidden']) return true;
    else return false;
}

function filtreNotHiddens($e) {
    if (isset($e['hidden']) && !$e['hidden']) return true;
    else return false;
}

$arrayToFiltre = array(
    array('hidden' => true, 'someKey' => 'someVal'),
    array('hidden' => false, 'someKey1' => 'someVal1'),
    array('hidden' => true, 'someKey2' => 'someVal3'),
);

$hidden = array_filter($arrayToFiltre, 'filtreHiddens');
$notHidden = array_filter($arrayToFiltre, 'filtreNotHiddens');

print_r($hidden);
print_r($notHidden);

Upvotes: 0

Viacheslav Kondratiuk
Viacheslav Kondratiuk

Reputation: 8879

$myArray = Array('item1', 'item2hidden', 'item3', 'item4', 'item5hidden');
$arr1 = array();
$arr2 = array();    
foreach ($myArray as $item) {
    if (strpos($item, "hidden") !== false) {
        $arr1[] = $item;
    } else {
        $arr2[] = $item;
    }
}

This solution checks if 'hidden' present at current item, if no, move to $arr1 else to $arr2

Upvotes: 0

Vlad Preda
Vlad Preda

Reputation: 9920

This should do the trick:

$myArray = array('item1', 'item2hidden', 'item3', 'item4', 'item5hidden');
$secondaryArray = array();

foreach ($myArray as $key => $value) {
    if (strpos($value, "hidden") !== false) {
        $secondaryArray[] = $value;
        unset($myArray[$key]);
    }
}

It moves all the entries that contain "hidden" from the $myArray to $secondaryArray.

Note: It's case sensitive

Upvotes: 10

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