CODEWITHSUNDEEP
javascript
user1277170
user1277170

Reputation: 3227

Find caller script in JavaScript?

Consider these script fragments.

<script data-name="script1">
    foo();
</script>

<script data-name="script2">
    foo();
</script>

<script>
    function foo(){
//      console.log(arguments.?);
    }
</script>

Is there a way to find out which script function foo was called from the line denoted by the "//"?

Upvotes: 2

Views: 1715

Answers (2)

Rob M.
Rob M.

Reputation: 36511

Ok, I figured it out, this will grab the script data-name attribute

function foo() {
    var parentScript = document.body.lastChild;
    console.log(parentScript.getAttribute('data-name'));
}

To get it to work I had to define the foo function above the calls to it, but I'm sure some playing around with it could resolve that.

Upvotes: 0

rolfv1
rolfv1

Reputation: 571

As already mentioned in the comments, the way you present it, this is not possible, it only works if the function foo is called from a function, which then of course has to be a different function for each script, then you can use

console.log(arguments.callee.caller.name)

That will give you the name of the function that called your function foo.

Edit: and really, if it's important to know from where the script was called, just use an argument, like function foo(caller){, which indicates how the function was called, that's much safer than relying on the arguments.callee.caller thing.

Upvotes: 2

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