CODEWITHSUNDEEP
java
DrkVenom
DrkVenom

Reputation: 113

scanner is not storing strings past a "space"

Firstly, I'm very beginner, but I like to think I mildly understand things.

I'm trying to write a method that will store the user's input into a string. It works just fine, except if the user puts in a space. Then the string stops storing. 

public static String READSTRING()   {
        Scanner phrase = new Scanner(System.in);
        String text = phrase.next();
        return text;
    }

I think the problem is that phrase.next() stops scanning once it detects a space, but I would like to store that space in the string and continue storing the phrase. Does this require some sort of loop to keep storing it?

Upvotes: 1

Views: 191

Answers (4)

alanazi
alanazi

Reputation: 82

Try 

pharse.NextLine();

and you got do an array for limited words

String Stringname = {"word","word2"};

Random f = new Random(6);
 Stringname = f.nextInt();

and you can convert an integer to string

int intvalue = 6697;
 String Stringname = integer.ToString(intvalue);

Upvotes: 0

Chthonic Project
Chthonic Project

Reputation: 8366

From the Javadoc, this is what we have:

A Scanner breaks its input into tokens using a delimiter pattern, which by default matches whitespace.

Either you can use phrase.nextLine() as suggested by others, or you can use Scanner#useDelimiter("\\n").

Upvotes: 1

fritterdonut
fritterdonut

Reputation: 36

Try phrase.nextLine();. If I recall correctly, Scanner automatically uses spaces as delimiters.

Upvotes: 0

Jeroen Vannevel
Jeroen Vannevel

Reputation: 44449

Use .nextLine() instead of .next().

.nextLine() will take your input until a newline character has been found (when you press enter, a newline character is added). This essentially allows you to get one line of input.

Upvotes: 3

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