Reputation: 121
I have a list of lists that looks like this:
[['10.2100', '0.93956088E+01'],
['11.1100', '0.96414905E+01'],
['12.1100', '0.98638361E+01'],
['14.1100', '0.12764182E+02'],
['16.1100', '0.16235739E+02'],
['18.1100', '0.11399972E+02'],
['20.1100', '0.76444933E+01'],
['25.1100', '0.37823686E+01'],
['30.1100', '0.23552237E+01'],...]
(here it looks as if it is already ordered, but some of the rest of the elements not included here to avoid a huge list, are not in order)
and I want to sort it by the first element of each pair, I have seen several very similar questions, but in all the cases the examples are with integers, I don't know if that is why when I use the list.sort(key=lambda x: x[0])
or the sorter, or the version with the operator.itemgetter(0)
I get the following:
[['10.2100', '0.93956088E+01'],
['100.1100', '0.33752517E+00'],
['11.1100', '0.96414905E+01'],
['110.1100', '0.25774972E+00'],
['12.1100', '0.98638361E+01'],
['14.1100', '0.12764182E+02'],
['14.6100', '0.14123326E+02'],
['15.1100', '0.15451733E+02'],
['16.1100', '0.16235739E+02'],
['16.6100', '0.15351242E+02'],
['17.1100', '0.14040859E+02'],
['18.1100', '0.11399972E+02'], ...]
apparently what is doing is sorting by the first character appearing in the first element of each pair.
Is there a way of using list.sort
or sorted()
for ordering this pairs with respect to the first element?
Upvotes: 0
Views: 142
Reputation: 113988
dont use list as a variable name!
some_list.sort(key=lambda x: float(x[0]) )
will convert the first element to a float and comparit numerically instead of alphabetically
(note the cast to float is only for comparing... the item is still a string in the list)
Upvotes: 5