Reputation: 1455
How do I print out my dictionary in the original order I had set up?
If I have a dictionary like this:
smallestCars = {'Civic96': 12.5, 'Camry98':13.2, 'Sentra98': 13.8}
and I do this:
for cars in smallestCars:
print cars
it outputs:
Sentra98
Civic96
Camry98
but what I want is this:
Civic96
Camry98
Sentra98
Is there a way to print the original dictionary in order without converting it to a list?
Upvotes: 15
Views: 26484
Reputation: 25
The order of printing of a dictionary in Python depends on the version you're using: Python 3.7 and above:
Dictionaries are ordered. This means that they will print in the order in which the key-value pairs were inserted.
Python 3.6 and below: Dictionaries are unordered. This means that the printing order is arbitrary and not guaranteed to be the same as the insertion order.
Upvotes: 1
Reputation: 72965
You can use a tuple (nested) array to do this:
smallestCars = [['Civic86', 12.5],
['Camry98', 13.2],
['Sentra98', 13.8]]
for car, size in smallestCars:
print(car, size)
# ('Civic86', 12.5)
# ('Camry98', 13.2)
# ('Sentra98', 13.8)
Upvotes: 0
Reputation: 924
>>> for car in sorted(smallestCars.items(),key=lambda x:x[1]):
... print car[0]
...
Civic96
Camry98
Sentra98
Upvotes: 2
Reputation: 12180
A regular dictionary doesn't have order. You need to use the OrderedDict
of the collections
module, which can take a list of lists or a list of tuples, just like this:
import collections
key_value_pairs = [('Civic86', 12.5),
('Camry98', 13.2),
('Sentra98', 13.8)]
smallestCars = collections.OrderedDict(key_value_pairs)
for car in smallestCars:
print(car)
And the output is:
Civic96
Camry98
Sentra98
Upvotes: 21
Reputation: 880
When you create the dictionary, python doesn't care about in what order you wrote the elements and it won't remember the order after the object is created. You cannot expect it(regular dictionary) to print in the same order. Changing the structure of your code is the best option you have here and the OrderedDict is a good option as others stated.
Upvotes: 1