CODEWITHSUNDEEP
c++arraysstringlistint
user3001499
user3001499

Reputation: 811

List functionality c++

I have briefly looked around various c++ sites and text books. But none of them have had anything related to what I was looking for.

What I want is a list in c++ which can contain int, string and int array variables within it. But before I spend hours playing around with some code, I was wondering if anyone knew if such a thing actually exists? I'm not asking for code to be shown to me, if it is possible, I will attempt it, and then ask about any issues I have with it.

Thanks

Upvotes: 0

Views: 106

Answers (4)

westwood
westwood

Reputation: 1774

In case you meant an object that can contain int, string and arrays as separate objects, not as one (like union) -- I think you should take a look at C++11 tuples , and use them in list.

Upvotes: 2

holgac
holgac

Reputation: 1539

You can also create a struct using union or void pointer.

enum varType
{
    vt_int,
    vt_float,
    vt_string
}

class myVariant
{
private:
    void* mVariable;
    varType mType;
};

or also,

class myVariant2
{
private:
    union
    {
        float fValue;
        int iValue;
        std::string* sValue;        
    };
    varType mType;
}

It's not nice and would require casting heavily, but if you don't like using other libraries for such small task, this might be of help.

Edit1: You will need getStringValue, getFloatValue getIntValue functions.

Edit2: You can safely use this classes in std::list.

Edit3: You need to call destructor of std::string (if the variable is a string) yourself.

Upvotes: 0

samdu
samdu

Reputation: 16

It might be unsafe to put different types of objects/data in single list.

But if it the requirement, then why not derive new class from std::list with combination of keeping track of types being inserted into list using aproach mentioned in above answer.

Upvotes: 0

DarkWanderer
DarkWanderer

Reputation: 8866

Your best bet is boost::variant. Remember - I didn't tell you it will be easy.

Usage will be simple:

typedef boost::variant<...my necessary types...> MyVariant;

std::list<MyVariant> myList;

Upvotes: 5

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