Reputation: 1256
I try to represent a floating point number as a ratio of two integers, but for some reason the integers that I get are quite different from what I would expect to see. Can somebody explain this?
>>> value = 3.2
>>> ratios = value.as_integer_ratio()
>>> ratios
(3602879701896397, 1125899906842624)
>>> ratios[0] / ratios[1]
3.2
I would say that (32, 10)
or (16, 5)
are much better solutions to the problem. What's strange is that if I try to do the same for number like 2.5, the answer is exactly what I would expect
>>> value = 2.5
>>> value.as_integer_ratio()
(5, 2)
Upvotes: 10
Views: 9595
Reputation:
While using the fractions module, it is better to provide a string instead of a float to avoid floating point representation issues.
For example, if you pass '3.2'
instead of 3.2
you get your desired result:
In : fractions.Fraction('3.2')
Out: Fraction(16, 5)
If you already have the value stored in a variable, you can use string formatting as well.
In : value = 3.2
In : fractions.Fraction(f'{value:.2f}')
Out: Fraction(16, 5)
Upvotes: 3
Reputation: 1122092
Use the fractions
module to simplify fractions:
>>> from fractions import Fraction
>>> Fraction(3.2)
Fraction(3602879701896397, 1125899906842624)
>>> Fraction(3.2).limit_denominator()
Fraction(16, 5)
From the Fraction.limit_denominator()
function:
Finds and returns the closest
Fraction
toself
that has denominator at most max_denominator. This method is useful for finding rational approximations to a given floating-point number
Floating point numbers are limited in precision and cannot represent many numbers exactly; what you see is a rounded representation, but the real number is:
>>> format(3.2, '.50f')
'3.20000000000000017763568394002504646778106689453125'
because a floating point number is represented as a sum of binary fractions; 1/5 can only be represented by adding up 1/8 + 1/16 + 1/128 + more binary fractions for increasing exponents of two.
Upvotes: 20
Reputation: 142156
It's not 16/5 because 3.2
isn't 3.2 exactly... it's a floating point rough approximation of it... eg: 3.20000000000000017764
Upvotes: 5