CODEWITHSUNDEEP
c++char
halachkin
halachkin

Reputation: 37

Printing array of chars using pointer to char.

In main.cpp I must print my char array like this:

const char *str(CValue::TestStringValue0());
cout << ' ' << *str << endl; //must not change

I can't modify this! So I need to print my array of char, but nor first value of array.

TestStringValue look like this..

static const char* TestStringValue0() {...}

Upvotes: 0

Views: 199

Answers (2)

Vlad from Moscow
Vlad from Moscow

Reputation: 310980

const char *str(CValue::TestStringValue0());
const char *p = str;

for ( ; *str; ++str )
{
    cout << ' ' << *str << endl; //must not change
}

:)

Upvotes: 1

FreeNickname
FreeNickname

Reputation: 7764

I'm not sure I understand you correctly, but if you're not supposed to modify this line:

cout << ' ' << *str << endl; //must not change

Then you can do like this:

const char *tempStr(CValue::TestStringValue0());
const char **str = &tempStr;
cout << ' ' << *str << endl; //must not change

In this case cout will print the whole string returned from TestStringValue0, while in the original code it printed only the first char.

P.S. What a strange condition you have :)

Upvotes: 1

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