Reputation: 395
I am using multiple form in a page here is my HTML code:
<form name="myform" id="myform" method="post" action="test.php">
<a href="javascript: submitform();" >submit</a>
<input type="hidden" name="encKey" value="12" />
</form>
<form name="myform" id="myform" method="post" action="test.php">
<a href="javascript: submitform();" >submit</a>
<input type="hidden" name="encKey" value="12" />
</form>
<form name="myform" id="myform" method="post" action="test.php">
<a href="javascript: submitform();" >submit</a>
<input type="hidden" name="encKey" value="12" />
</form>
And here is my javascript code:
<script type="text/javascript">
function submitform()
{
document.myform.submit();
}
</script>
When i click on submit link, form is not submitting and gererate error in backend:
TypeError: document.myform.submit is not a function.
What may be issue?
Thanks
Upvotes: 0
Views: 1333
Reputation: 1
the id of a form must be unique, try to change the form id to only name.
you can try to use
document.getElementById('formId').submit()to submit the information of a form.
Upvotes: 0
Reputation: 23793
First of all you've got 3 id which are the same (myform), an id has to be unique.
Upvotes: 0
Reputation: 148
You can also use document.forms["myForm"].submit();
.
In this case "myForm"
is the name of each form and it has to be unique as well as id.
Upvotes: 0
Reputation: 8001
I think you should use unique ids for all the forms. Then you can have a function that takes as a parameter the id of the form that you want to submit and then submit it. So you can have something like
<script type="text/javascript">
function submitform(formid)
{
document.getElementById(formid).submit();
}
</script>
Upvotes: 1
Reputation: 9199
You may try this
<script type="text/javascript">
function submitform()
{
document.getElementById('myform').submit();
}
</script>
Upvotes: 0