CODEWITHSUNDEEP
javascriptphp
bobbyjones
bobbyjones

Reputation: 2077

insert key=>value pair in PHP from a submitted Javascript object

im trying to figure out how to properly insert key=>value pair to an array using array_unshift

this is my code.

Javascript/AJAX

var array= {};
array['name'] = name;
array['lname'] = lname;

$.ajax ({ 
   type:"POST",
   url:"some.php",
   data: {array:array},
   success: function(html) {}
});

PHP will then receive the array via POST

$array = $_post['array'];

//add additional key=>value pair in the array
array_unshift($array, "['middle']=>test");
return $array;

Im not getting any errors from it, i just dont see the value being printed from the function.

Printed Result:

Object {name: "John", lname: "Smith"}

edit:typo

Upvotes: 0

Views: 198

Answers (3)

Tim S.
Tim S.

Reputation: 13843

I don't think you're doing it right...

You can't alter a JavaScript array (it's an object actually) via PHP. However, you can fetch new data and replace the JavaScript object.

Because I'm expecting an object, I might as well use the JSON format - thus use $.getJSON() instead. Note that this is a GET request on default.

var url = 'file.php';
var obj = {
    name: name,
    lname: lname
};

$.getJSON(url, { data:obj }, function(data) {
    // replace object with new content
    obj = data;
    console.log(obj);
});

As for your PHP code:

// get data (remember we're using a GET request)
$data = $_GET['data'];

// add an index
$data['middle'] = 'test';

// echo data in JSON format
echo json_encode($data);

Upvotes: 1

GautamD31
GautamD31

Reputation: 28753

Rename the person to array like

var array= {};
array['name'] = name;
array['lname'] = lname;

$.ajax ({ 
   type:"POST",
   url:"some.php",
   data: {array:array},
   success: function(html) {}
});

Or send the person array as array

data: {array:person},

EDIT :.Simple try like

$array['middle'] = 'test';

Upvotes: 0

Ankit Tyagi
Ankit Tyagi

Reputation: 2375

// not var array= {};
var person = {}
person['name'] = name;
person['lname'] = lname;

Upvotes: 0

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