CODEWITHSUNDEEP
cswitch-statementturbo-c++
Pawan Joshi
Pawan Joshi

Reputation: 1579

Unexpected Behaviour of Switch-Case in C

I Came across a problem in a book, when i ran the code in MSDOSBox TurboC++ For Windows 7, it showed me unexpected behaviour :-

the code was as follows :-

#include <stdio.h>
#include <conio.h>
void main()
{
   char s = 3;
   switch(s)
   {
       case 1 :
       printf("\nDiamond");
       break;
       case 2 :
       printf("\nSpades");
       break;
       default :
       printf("\nHeart");
       break;
   }
   printf("\nI thought something like this");
   getch();
}

now the problem was…

the statement in default case was never got printed. it only printed "I thought something like this"

I gathered that in switch-case char is treated as its value in ASCII code

Well… here, the value to char s has been given 3 not '3' but again at least default case should be printed even if the value is nothing like any of the cases

well… if this helps..

i have tried to put

case 3 :

instead of

default :

now the statement i.e printf("\nHeart"); got executed and printed "Heart" on the screen

Upvotes: 0

Views: 221

Answers (1)

Joe Z
Joe Z

Reputation: 17956

Did you cut/paste this code from your source, or retype it? If you retyped it, go back and make sure you spelled default correctly in the original.

A common error that usually elicits no warning from the compiler is to type something like defualt instead of default for that last label.

Upvotes: 3

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