CODEWITHSUNDEEP
javaexception
user2954611
user2954611

Reputation: 57

Number Format Exception, really stuck

hereis my code.... I am getting a NumberFormatException and idk whow to solve it.. newbie and totally stuck, really need the help

public class AcccountArray {

    public static void main(String[] args) 
    {
        //Scan the file and save account details to array
        File file = new File ("customers.txt");
        System.out.println("Path : " + file.getAbsolutePath());
        try{
                    Scanner scanner = new Scanner("customers.txt");
                    String[][] Account = new String[Integer.valueOf(scanner.nextLine())][3];

                    for(int i=0;i<Account.length;i++)
                    {
                        Account[i][0]=scanner.nextLine();
                        //System.out.println(Account[i][0]);
                        Account[i][1]=scanner.nextLine();
                        //System.out.println(Account[i][1]);
                        Account[i][2]=scanner.nextLine();
                        //System.out.println(Account[i][2]);
                    }
                    scanner.close();

error:

java.lang.NumberFormatException: For input string: "customers.txt"
    at java.lang.NumberFormatException.forInputString(Unknown Source)
    at java.lang.Integer.parseInt(Unknown Source)
    at java.lang.Integer.valueOf(Unknown Source)
    at AcccountArray.main(AcccountArray.java:15)

li. 15 is 

String[][] Account = new String[Integer.valueOf(scanner.nextLine())][3];

Upvotes: 0

Views: 144

Answers (1)

Reimeus
Reimeus

Reputation: 159874

Use the constructor for Scanner that accepts a File so that the scanner instance is not using a String source:

Scanner scanner = new Scanner(new File("customers.txt"));

Since you already have this reference you can use

Scanner scanner = new Scanner(file);

Upvotes: 4

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