CODEWITHSUNDEEP
javaregexstring
gadu
gadu

Reputation: 1826

How to get all substrings occurring between two characters?

If I wanted to pull all substrings between two characters(general) along a String how would I do that? I also want to keep the first char I match but not the second one.

So, for example, if I wanted ot keep the characters between a # char and either the next whitespace OR next of another char (in this case # again, but could be anything) and I had a string, say : "hello i'm #chilling#likeAVillain but like #forreal"

How would I get, say a Set of [#chilling, #likeAVillain, #forreal]

I'm having difficulty because of the either/or end substring case - I want the substring starting with # and ending before the first occurence of either another # or a whitespace (or the end of the string if neither of those are found)

Put simplest in sudocode:

for every String W between [char A, either (char B || char C)) // notice [A,B) - want the 
                                                               //first to be inclusive
   Set.add(W);

Upvotes: 2

Views: 2284

Answers (2)

Pshemo
Pshemo

Reputation: 124265

This regex #\\w+ seems to do what you need. It will find # and all alphanumeric characters after it. Since whitespace is not part of \\w it will not be included in your match.

String s = "hello i'm #chilling#likeAVillain but like #forreal";
Pattern p = Pattern.compile("#\\w+");
Matcher m = p.matcher(s);
while (m.find())
    System.out.println(m.group());

output:

#chilling
#likeAVillain
#forreal

Upvotes: 3

user3020494
user3020494

Reputation: 732

public static void main(String[] args) throws Exception{

    String s1 = "hello i'm #chilling#likeAVillain but like #forreal";
    String[] strArr = s1.split("\\#");
    List<String> strOutputArr = new ArrayList<String>();
    int i = 0;
    for(String str: strArray){

        if(i>0){
            strOutputArray.add("#" + str.split("\\s+")[0]);
        }
        i++;
    }
    System.out.println(strOutputArray.toString());

    }

Upvotes: 0

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