CODEWITHSUNDEEP
javaregexsplit
user3003233
user3003233

Reputation: 31

Split String to float and string

How can i split 100.26kg to System.out.println as 

100.26
kg

I tried doing by using ("\d+") but was not successful. 

String[] num = myTextCount.split("\\d+");

The 100.26kg may vary according to user input. It could be 100.26kg, 100g, 100 pounds or 100litre. If there is any way to split the number and alphabet, it will be very helpful

Upvotes: 2

Views: 1576

Answers (6)

BLUEPIXY
BLUEPIXY

Reputation: 40145

import java.util.Scanner;

public class Sample {
    public static void main(String[] args) {
        String inputs[] = { "100.26kg", "100g", "100 pounds", "100litre"};

        String weight, unit;

        for(String input : inputs){
            Scanner scan = new Scanner(input);
            weight = scan.findInLine("\\d+(\\.\\d+)?");
            unit = scan.next();//scan.next("\\w+");

            System.out.println(weight);
            System.out.println(unit);
        }
    }
}

Upvotes: 0

Masudul
Masudul

Reputation: 21971

Try look-around regex,

  String[] num = myTextCount.split("(?<=\\d)(?=[a-z])|(?<=[a-z])(?=\\d)");

If you want to split case-insensitive with number than use (?i) 

 String[] num = myTextCount.split("(?i)(?<=\\d)(?=[a-z])|(?<=[a-z])(?=\\d)");

Upvotes: 1

Artur
Artur

Reputation: 7257

Matcher m = Pattern.compile("^([0-9.]+)\\s*([a-zA-Z]+)$").matcher("");
String inputs[] = {"100.26kg", "1 pound", "98gallons" };

for(String input: inputs)
{
    if ( m.reset(input).find() )
    {
        System.out.printf("amount=[%s] unit=[%s]\n", m.group(1), m.group(2) );
    }
}

yields:

amount=[100.26] unit=[kg]
amount=[1] unit=[pound]
amount=[98] unit=[gallons]

Upvotes: 0

dandy1992
dandy1992

Reputation: 11

Do not use Split, just use the String.IndexOf() function to deal with it.

Upvotes: 0

tylucaskelley
tylucaskelley

Reputation: 131

Try this:

private static final Pattern VALID_PATTERN = Pattern.compile("[0-9]+|[A-Z]+");

private List<String> parse(String toParse) {
    List<String> chunks = new LinkedList<String>();
    Matcher matcher = VALID_PATTERN.matcher(toParse);
    while (matcher.find()) {
        chunks.add( matcher.group() );
    }
    return chunks;
}

This solution is quite modular as well.

Upvotes: -1

Wang Jun
Wang Jun

Reputation: 595

myTextCount.split("[\\.\\d]+") will give you [, kg] which contain the second part, and then use #indexOf() to find the first part.

Upvotes: 1

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