CODEWITHSUNDEEP
pythonfor-loopprinting
user2982959
user2982959

Reputation: 41

Print lines with numbers infront

I am currently trying to print a list of objects where each new line gets a number infront of it. Like the first line has a 1 infront of it, the second has a 2 etc. The print function works fine when I am not using the numbers for each line.

I tried to write it:

n=0
for x in List:
   print("\n".join(str(n,x))
   n+=1

The List in this case contains a bunch of objects, all having 4 attributes, self.name, self.randomint, self.randomint2, self.randomint3

But I am getting an invalid syntax doing this, would appreciate help!

Upvotes: 0

Views: 1553

Answers (2)

Martijn Pieters
Martijn Pieters

Reputation: 1124110

You missed a closing parenthesis:

print("\n".join(str(n,x))
#                --------^

but that's not a correct statement still as str() takes one string argument with optional encoding.

It'll be easier to use enumerate() to add a count, and pass in two arguments to print():

for n, x in enumerate(Line):
    print(n, x)

Upvotes: 1

falsetru
falsetru

Reputation: 369364

The parentheses are unbalanced in the following line:

   print("\n".join(str(n,x))

Replace it with:

   print("\n".join(str(n,x)))
   #                        ^

Another issue: str accepts only one argument.

>>> str(1, 2)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: str() takes at most 1 argument (2 given)
>>> str(1)
'1'

Complete example code:

n=0
for x in List:
    print(n, x)
    n += 1

using enumerate:

for n, x in enumerate(List, 1):
    print(n, x)

Upvotes: 2

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