CODEWITHSUNDEEP
xmlxsltxpath
AlexPandiyan
AlexPandiyan

Reputation: 4655

Find node in XML path?

How to get single child node?

<root>
   <p><span>text</span><span>text</span><span>text</span></p>
   <p><span>text</span></p>
   <p><span>text</span><span>text</span><span>text</span></p>
   <p><span>text</span></p>
</root>

for example: /root/p/span

I can get all span tag and I can find the first child or last child or child, but I need to find one child para randomly. How can I get that para tag by XML path?

Upvotes: 0

Views: 219

Answers (2)

Mathias M&#252;ller
Mathias M&#252;ller

Reputation: 22617

Based on your clarifications, this is how you can select p elements only if they contain exactly one span element.

<?xml version="1.0" encoding="utf-8"?>

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output method="xml" indent="yes"/>

<xsl:template match="/">
  <xsl:apply-templates/>
</xsl:template>

<xsl:template match="root">
  <xsl:apply-templates/>
</xsl:template>

<xsl:template match="p[count(span)=1]">
  <xsl:copy>
     <xsl:copy-of select="*|text()"/>
  </xsl:copy>
</xsl:template>

<xsl:template match="*"/>

</xsl:stylesheet>

Input XML I used:

<?xml version="1.0" encoding="utf-8"?>

<root>
<p>
  <span>wrong</span>
  <span>wrong</span>
  <span>wrong</span>
</p>
<p>
  <span>right</span>
</p>
<p>
  <span>wrong</span>
  <span>wrong</span>
  <span>wrong</span>
</p>
<p>
  <span>right</span>
</p>
</root>

Output XML:

<?xml version="1.0" encoding="UTF-8"?>

<p>
  <span>right</span>
</p>

<p>
  <span>right</span>
</p>

Upvotes: 1

Mathias M&#252;ller
Mathias M&#252;ller

Reputation: 22617

Randomly choosing items is not part of standard XSLT as such because it is a functional language. In other words, it is guaranteed that you arrive at the same output for a given input no matter how many times you try.

However, if randomness is essential to you, use extensions to XSLT. Answers are suggested here:

Dimitre's libraries referenced there could be exactly what you need. Note that the precondition for random assignment is a random number and therefore that is the focus of discussion.

Upvotes: 0

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