CODEWITHSUNDEEP
linuxbashshell
Jafar Kofahi
Jafar Kofahi

Reputation: 763

Ignore folder and its files from search results

I have a special requirement where I have to use a separate command to filter out all folders and their files from the search result in Linux!

Example: I have the following folders, and they all have a file called test

/testfolder/f1
/testfolder/f1_0VT0_hc1
/testfolder/f1_0VT0_hc2

So for example if I run ls testfolder/* the initial results would be:

/testfolder/f1:
test

/testfolder/f1_0VT0_hc1:
test

/testfolder/f1_0VT0_hc2:
test

I need to pipe in another command (e.g. grep) that would take in that result and filter out all directories that have the _0VT0_ and their files!

I was able to ignore the directories using :

ls testfolder/* | grep -R --exclude-from='.*_0VT0_.*'

but I still got the files!

Question: how can I modify my grep command or what command should I use to ignore the folders and the files within them!

Clarification I will be given an ls or find command and I need another command to execute after them that will filter out such folders and their files. So something I can pipe or do in a batch file.

Upvotes: 0

Views: 73

Answers (1)

Barmar
Barmar

Reputation: 780688

Use the -prune option to find.

find * -name '*_0VT0_*' -prune -o -print

You can use this as part of another command with ordinary command substitution:

ls -d $(find * -name '*_0VT0_*' -prune -o -print)

Upvotes: 2

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