CODEWITHSUNDEEP
pythonfor-loopsequence
Matthias Pospiech
Matthias Pospiech

Reputation: 3488

python: iteration over non sequence error with linspace

I have defined my own linspace command to generate a vector of elements. The iteration over this vector however fails with iteration over non sequence of type int

This is the linspace

def linspace(a, b, n=100):
    if n < 2:
        return b
    diff = (float(b) - a)/(n - 1)
    # return [diff * i + a  for i in range(n)]
    linlist = []
    for i in range(n):
        linlist.append(diff * i + a)
    return linlist

and this my for loop 

n = (beginPos - endPos) / diff + 1
positions = linspace(beginPos, endPos, n)
for z in positions:
    ## Move to new position
    MoveTo(z)

I have no idea why the positions variable is not a valid sequence .

EDIT: It was my definition of n the number n was negative, it needs to be calculated as 

n = abs((beginPos - endPos) / diff) + 1

Upvotes: 0

Views: 449

Answers (1)

falsetru
falsetru

Reputation: 369344

If n is less than 2, linspace return b, not a list.

if n < 2:
    return b # <----

>>> def linspace(a, b, n=100):
...     if n < 2:
...         return b
...     diff = (float(b) - a)/(n - 1)
...     # return [diff * i + a  for i in range(n)]
...     linlist = []
...     for i in range(n):
...         linlist.append(diff * i + a)
...     return linlist
...
>>> linspace(1, 100, n=1)
100
>>> for z in linspace(1, 100, n=1): pass
...
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: 'int' object is not iterable

Adjust return b to return a list.

Upvotes: 1

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