CODEWITHSUNDEEP
c#asp.netservertag
bunnie
bunnie

Reputation: 65

The Server tag is not well formed error in a Wizard

I am getting the "The Server tag not well formed error". Please see the below code:

<ul id="wizHeader">
               <asp:Repeater ID="SideBarList" runat="server">
                   <ItemTemplate>

                       <li>
                           <asp:LinkButton runat="server" CssClass="<%# GetClassForWizardStep(Container.DataItem) %>" Font-Bold="true" ID="SideBarButton" OnClick="Step_Click" Text="<%# Eval("Name") %>" ToolTip="<%# Eval(ID) %>"></asp:LinkButton>
                       </li>

                   </ItemTemplate>
               </asp:Repeater>
           </ul>

Upvotes: 1

Views: 139

Answers (2)

Ashish Charan
Ashish Charan

Reputation: 2387

Alternatively you can use a simple anchor tag and apply all bindings to it. And make it cause the same postback as your button was doing. Example:

   <a onClick="javascript:__doPostBack('<%= SideBarButton.UniqueID %>')" class="<%# GetClassForWizardStep(Container.DataItem) %>"> <%# Eval("Name") %></a>

After doing this, you would have to hide the link button by settings its css display property none.

Long work around. :)

Upvotes: 0

Luaan
Luaan

Reputation: 63772

You can't use <%# inside of server controls' attribute.

So if you want to use a LinkButton inside of the Repeater, you have to bind the attributes in code-behind using the Repeater.ItemDataBound event.

Example from MSDN: http://msdn.microsoft.com/en-us/library/system.web.ui.webcontrols.repeater.itemdatabound(v=vs.110).aspx

Upvotes: 3

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