Reputation: 163
If I have a while loop that goes through a file and prints the numbers, how would I make it to where it only prints the very last number.
0
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
This is the output I'm currently getting. How would I make get it to where it would just print out 19
And how would I get it to work to where the numbers start at 1 instead of 0?
Currently my loop looks like this:
if (math == last){
System.out.println(Score++);
}
math is another method which computes equations, and last is the answer inputed from a file, and the loop currently just checked if the math matches the inputed answer in order to "grade" the problems.
I can't use arrays, try/catch, or regex.
Upvotes: 0
Views: 2362
Reputation: 94429
Just read through the file normally and store each line in a temporary variable. Once the reader finishes reading, print out the temporary variable.
public class ReaderExample {
public static void main(String[] args) throws IOException {
File file = new File("input.txt");
BufferedReader br = new BufferedReader(new FileReader(file));
String line = "";
String copy = "";
while((line = br.readLine() )!= null){
copy = line;
}
System.out.println(copy);
}
}
Using a Scanner
The same principle applies with a Scanner
:
public class ReaderExample {
public static void main(String[] args) throws IOException {
Scanner in = new Scanner(new FileReader("input.txt"));
String line = "";
while(in.hasNext()){
line = in.nextLine();
}
System.out.println(line);
}
}
Without Invoking Scanner
public String getLast(Scanner scanner){
String line = "";
while(in.hasNext()){
line = in.nextLine();
}
return line;
}
Upvotes: 2