CODEWITHSUNDEEP
javascriptdatetime
steven
steven

Reputation: 13537

How do I calculate how many seconds between two dates?

So I have two dates YYYY-MM-DD and ZZZZ-NN-EE

How can I find out how many seconds there are between them?

Upvotes: 257

Views: 255615

Answers (10)

Alex Holiber
Alex Holiber

Reputation: 33

function parseDate(str) {
  const [dateStr, timeStr] = str.split(' ');
  const [m,d,y] = dateStr.split('/');
  const [h,min] = timeStr.split(':');
  const date = new Date(y,m,d,h,min,0, 0);
  
  return date;
}

const date1 = parseDate('28/6/2022 22:55');
const date2 = parseDate('28/6/2022 22:58');
const diffInSeconds = (date2 - date1) / 1000;

console.log(diffInSeconds)

Upvotes: 0

Seth
Seth

Reputation: 46423

Just subtract:

var a = new Date();
alert("Wait a few seconds, then click OK");

var b = new Date();
var difference = (b - a) / 1000;

console.log("You waited: " + difference + " seconds");

Upvotes: 117

Fernando Pie
Fernando Pie

Reputation: 895

Easy Way:

function diff_hours(dt2, dt1) 
 {

  var diff =(dt2.getTime() - dt1.getTime()) / 1000;
  diff /= (60 * 60);
  return Math.abs(Math.round(diff));

 }


function diff_minutes(dt2, dt1) 
 {

  var diff =(dt2.getTime() - dt1.getTime()) / 1000;
  diff /= (60);
  return Math.abs(Math.round(diff));

 }

function diff_seconds(dt2, dt1) 
 {

  var diff =(dt2.getTime() - dt1.getTime()) / 1000;
  return Math.abs(Math.round(diff));

 }

function diff_miliseconds(dt2, dt1) 
 {

  var diff =(dt2.getTime() - dt1.getTime());
  return Math.abs(Math.round(diff));

 }


dt1 = new Date(2014,10,2);
dt2 = new Date(2014,10,3);
console.log(diff_hours(dt1, dt2));


dt1 = new Date("October 13, 2014 08:11:00");
dt2 = new Date("October 14, 2014 11:13:00");
console.log(diff_hours(dt1, dt2));

console.log(diff_minutes(dt1, dt2));

console.log(diff_seconds(dt1, dt2));

console.log(diff_miliseconds(dt1, dt2));

Upvotes: 6

Martin
Martin

Reputation: 12403

I'm taking YYYY & ZZZZ to mean integer values which mean the year, MM & NN to mean integer values meaning the month of the year and DD & EE as integer values meaning the day of the month. 

var t1 = new Date(YYYY, MM, DD, 0, 0, 0, 0);
var t2 = new Date(ZZZZ, NN, EE, 0, 0, 0, 0);
var dif = t1.getTime() - t2.getTime();

var Seconds_from_T1_to_T2 = dif / 1000;
var Seconds_Between_Dates = Math.abs(Seconds_from_T1_to_T2);

A handy source for future reference is the MDN site

Alternatively, if your dates come in a format javascript can parse

var dif = Date.parse(MM + " " + DD + ", " + YYYY) - Date.parse(NN + " " + EE + ", " + ZZZZ);

and then you can use that value as the difference in milliseconds (dif in both my examples has the same meaning)

Upvotes: 333

user5945979
user5945979

Reputation:

You can do it simply.

var secondBetweenTwoDate = Math.abs((new Date().getTime() - oldDate.getTime()) / 1000);

Upvotes: 25

Alex G
Alex G

Reputation: 211

In bash:

bc <<< "$(date --date='1 week ago' +%s) - \
    $(date --date='Sun,  29 Feb 2004 16:21:42 -0800' +%s)"

It does require having bc and gnu date installed.

Upvotes: -3

Jeff.Crossett
Jeff.Crossett

Reputation: 315

.Net provides the TimeSpan class to do the math for you.

var time1 = new Date(YYYY, MM, DD, 0, 0, 0, 0)
var time2 = new Date(ZZZZ, NN, EE, 0, 0, 0, 0)

Dim ts As TimeSpan = time2.Subtract(time1)

ts.TotalSeconds

Upvotes: -12

rmeador
rmeador

Reputation: 25696

If one or both of your dates are in the future, then I'm afraid you're SOL if you want to-the-second accuracy. UTC time has leap seconds that aren't known until about 6 months before they happen, so any dates further out than that can be inaccurate by some number of seconds (and in practice, since people don't update their machines that often, you may find that any time in the future is off by some number of seconds).

This gives a good explanation of the theory of designing date/time libraries and why this is so: http://www.boost.org/doc/libs/1_41_0/doc/html/date_time/details.html#date_time.tradeoffs

Upvotes: 16

Jacob Relkin
Jacob Relkin

Reputation: 163228

create two Date objects and call valueOf() on both, then compare them.

JavaScript Date Object Reference

Upvotes: 6

Justin Johnson
Justin Johnson

Reputation: 31300

var a = new Date("2010 jan 10"),
    b = new Date("2010 jan 9");

alert(
    a + "\n" + 
    b + "\n" +
    "Difference: " + ((+a - +b) / 1000)
);

Upvotes: 6

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