mikswe
mikswe

Reputation: 51

Combine two tables and echo out the result (PHP MYSQL)

I have two tables; 'client' and 'sys_notes' in the same DB. (SELECT client.*, sys_notes.* FROM client LEFT JOIN sys_notes ON sys_notes.client_id = client.id ORDER BY create_date DESC)

I need to combine the two tables echo in the same <div>content</div>, like this:

echo all from client = first.name + last.name (e.g. Scott)
echo all from client = role
echo all from client = whatever else
echo all from sys_notes sent by Robert Scott = note1, note2, note3, note(etc.)...
echo all from client = whatever else
echo all from client = whatever else

example output:


<div class="content">

Robert Scott
Supervisor
Robert works at the order office at the firm.
Robert´s notes:

Robert´s Phone: 000 000 000
Robert´s E-mail: etc.
Other information about Robert: ............

</div>

<div class="content">

Lisa Johansson
Supervisor
Lisa works at the marketing dep.
Lisas´s notes:

Lisa´s Phone: 000 000 000
Lisa´s E-mail: etc.
Other information about Lisa: ............

</div>

When i echo results today Robert is being "echoed" as many times he has notes,
with one note in each <div class="content">. (In example over Robert has 3 notes & 3 different Robert-div is echoed.)

Please help.

--- UPDATE ---

-- Table structure for table `sys_notes`

CREATE TABLE IF NOT EXISTS `sys_notes` (
  `note_id` int(11) NOT NULL AUTO_INCREMENT,
  `client_id` int(11) NOT NULL,
  `note_created` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
  `owning_user` varchar(50) NOT NULL,
  `note` varchar(500) NOT NULL,
  PRIMARY KEY (`note_id`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8 AUTO_INCREMENT=12 ;

-- Table structure for table `client`

CREATE TABLE IF NOT EXISTS `client` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `create_date` datetime NOT NULL,
  `first_name` varchar(50) NOT NULL,
  `last_name` varchar(50) NOT NULL,
  `phone` varchar(20) NOT NULL,
  `email` varchar(50) NOT NULL,
  `issue` varchar(50) NOT NULL,
  `other` longtext NOT NULL,
  `owning_user` int(11) NOT NULL,
  `status` varchar(10) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8 AUTO_INCREMENT=1081 ;

Upvotes: 1

Views: 778

Answers (2)

Lashus
Lashus

Reputation: 399

use:

SELECT DISTINCT

instead of:

SELECT

or GROUP BY statement.

-- EDIT --

Example echo:

$result = $db->query("SELECT client.*, GROUP_CONCAT(sys_notes.note SEPARATOR "|") as note, sys_notes.* FROM client LEFT JOIN sys_notes ON sys_notes.client_id = client.id GROUP BY sys_notes.client_id ORDER BY create_date DESC");

ob_start();
?>

<div class="content">

<?php
foreach($result as $row) {

    sprintf("<p>%s %s<br />%s<br />%s</p> %s <ul>", $row['firstname'], $row['lastname'], $row['role'], $row['desc'](example));

    foreach(explode("|", $row['note']) as $note) {
        sprintf("<li>%s</li>", $note);
    }

    sprintf("</ul>");
}
?>
</div>
<?

$result = ob_end_clean();

echo $result;

-- FINAL UPDATE --

<?php

try {
    $db = new PDO($dsn, $user, $password);
} catch (PDOException $e) {
    echo 'Connection failed: ' . $e->getMessage();
}

$result = $db->query('SELECT client . * , GROUP_CONCAT( sys_notes.note SEPARATOR  "|" ) AS n, sys_notes.* 
FROM client
LEFT JOIN sys_notes ON sys_notes.client_id = client.id
GROUP BY sys_notes.client_id
ORDER BY create_date DESC');

ob_start();
?>

<div class="content">

<?php

foreach($result as $row) {

    printf("<p>%s %s<br />%s</p> %s <ul>", $row['first_name'], $row['last_name'], $row['issue'], $row['other']);

    foreach(explode("|", $row['n']) as $note) {
        printf("<li>%s</li>", $note);
    }

    printf("</ul>");
}
?>
</div>
<?php

ob_end_flush();

Upvotes: 1

AAA
AAA

Reputation: 142

Steps:

1.Make Array
2.you use while loop for iterating complete if first+lastname is same then use same array index 
3. within loop make array like $a['notes'][]=$row['NOTES'];

then echo above array

Upvotes: 0

Related Questions