CODEWITHSUNDEEP
phparrays
Rakesh Bitling
Rakesh Bitling

Reputation: 39

Return value from array_push() is an integer instead of the populated array

My code is as follows:

foreach ($row_result as $results)
{
  $f = fopen("jigsaw.csv", "a+");
  $new_array = array();
  $content = $results->findElement(WebDriverBy::className('seo-company'))->geTtext();
  $test = array();
  if ($i == 1)
  {
    $Orgnisation_name = $content;
    $concate = array_push($test,$Orgnisation_name);
    echo "\n";
  }  
  if ($i == 2)
  {
    echo $Website = $content;
    echo "\n";
  }  
  if ($i == 3)
  {
    echo $HeadQuarters = $content;
    echo "\n";
  }  
  if ($i == 4)
  {
    echo $Phone = $content;
    echo "\n";
  }  
  if ($i == 5)
  {
    echo $Industries = $content;
    echo "\n";
  }  
  if ($i == 6)
  {
    echo $Employees = $content;
    echo "\n";
  }  
  if ($i == 7)
  {
    echo $Revenue = $content;
    echo "\n";
  }  
  if ($i == 8)
  {
    echo $Ownership = $content;
    echo "\n";
  }  
  $i++;
}

Here I want to push one by one element into concate array and finally save it into mysql php database.

When I try to push it into concate array its printing me 1 which is wrong.

What should I do?

Upvotes: 0

Views: 96

Answers (2)

aland
aland

Reputation: 2014

Do you need to use array_push? $concate = array_push($test,$Orgnisation_name); $test is blank at this point. If you just want to add an item to the $concate array, $concate[] = $Orgnisation_name; is enough.

Upvotes: 1

Viacheslav Kondratiuk
Viacheslav Kondratiuk

Reputation: 8889

array_push return value is:

Returns the new number of elements in the array.

So 1 is the number of elements in array.

Seems that you will always have 1, because you call $i++ and according to your code, block with array_push will be executed once.

Upvotes: 2

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