CODEWITHSUNDEEP
javaarraysreverse
braindead
braindead

Reputation: 65

Reverse printing of an array

(Java beginner) I came up with a code that would display an int array in reverse and although I know there's probably a better way to do it, I think this logic should work:

for(int i = 0, j = numList.length - 1; i < j; i++, j--)
    {
        int temp = numList[i];
        numList[i]  = numList[j];
        numList[j] = temp;
        System.out.print("Reverse order: " + temp + " ");
    }

What I don't understand is that when I enter 5 numbers, the console only shows the first two numbers and it ends there:

1
2
3
4
5
Reverse order: 1 2

What's wrong here and what can I do to fix it?

Upvotes: 0

Views: 199

Answers (2)

Dylan Meeus
Dylan Meeus

Reputation: 5802

That code is just faulty. Use this instead.

for(int i = numList.Length - 1; i >= 0;i--)
{
    int temp = numList[i];
    System.out.print("Reverse order: " + temp + " ");
}

In your code, you increment i and decrement j, meaning that if you'd loop untill your condition is satisfied, you'd get about half the loop done. Try and create a table of the values of your loop step by step, you'll see what I mean :)

Upvotes: 2

Nazgul
Nazgul

Reputation: 1902

i++ and j-- along with the loop iteration condition of i < j would become false when i and j reach the middle of the array. So essentially your for loop is only working up the first half of the loop. I didnt run you code but this is the first observation i made.

Upvotes: 0

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