CODEWITHSUNDEEP
php
Pedram Behroozi
Pedram Behroozi

Reputation: 2497

php - passing an operator to a function

Is it possible to pass an operator to a function? Like this:

function operation($a, $b, $operator = +) {
    return $a ($operator) $b;
}

I know I could do this by passing $operator as a string and use switch { case '+':... }. But I was just curious.

Upvotes: 0

Views: 1907

Answers (4)

GrumpyCrouton
GrumpyCrouton

Reputation: 8621

I know you specifically mention not using a switch statement here, but I think it's important to show how this could be set up using switch statements as in my opinion it is the easiest, safest, and most convenient way to do this.

function calculate($a, $b, $operator) {
    switch($operator) {
        case "+":
            return $a+$b;
        case "-":
            return $a-$b;
        case "*":
            return $a*$b;
        case "/":
            return $a/$b;
        default:
            //handle unrecognized operators
    }
    return false;
}

Upvotes: 0

Tarun
Tarun

Reputation: 3165

This can be done using eval function as 

function calculate($a,$b,$operator)
{

    eval("echo $a $operator $b ;");
}

calculate(5,6,"*");

Thanks.

Upvotes: 2

Krish R
Krish R

Reputation: 22721

Try, You cannot able to pass the operators in functions, YOU CAN USE FUNCTION NAME LIKE ADDITION, SUBTRACTION, MULTIPLICATION ... etc, 

function operation($a, $b, $operator ='ADDITION') {

     $operator($a, $b);
}

 function ADDITION($a, $b){
       return $a + $b;
 }

Upvotes: 1

ormurin
ormurin

Reputation: 377

It's not possible to overload operators in php, but there is a workaround. You could e.g. pass the functions add, sub, mul and etc.

function add($a, $b) { return $a+$b; }
function sub($a, $b) { return $a-$b; }
function mul($a, $b) { return $a*$b; }

And then you function would be something like:

function operation($a, $b, $operator = add) {
    return $operator($a, $b);
}

Upvotes: 6

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