CODEWITHSUNDEEP
javascriptregex
Maris
Maris

Reputation: 4776

Regular expression, all entries of #valueN# in string

I have a next string - "#Value# #value2# (#value3#) .. #valueN#" I need to write an regexp to get an array ["Value", "#value2#", "#value3#", "valueN"]

I've tryied next:

  var regexp = /#([A-z]+)#/gi;
  var string = "#Value# #value2# (#value3#) .. #valueN#";
  string.match(regexp);

But I get only first and last entry of expression in the string, but I need to get all entries.

Notice that the entire string can change over the time, I need to get all entries of text between # symbols.

Thx for any advance.

Upvotes: 0

Views: 190

Answers (1)

falsetru
falsetru

Reputation: 369034

The regular expression is missing digit part ([0-9] or \d):

> "#Value# #value2# (#value3#) .. #valueN#".match(/#[a-z\d]+#/ig)
["#Value#", "#value2#", "#value3#", "#valueN#"]

BTW, /[A-z]/ matches not only alphabet, but also characters between Z and a: [, \, ], ^, _, `. Be careful!

/[A-z]/.test('[')
true

Maybe you mean /[A-Za-z]/ or /[A-Z]/i or /[a-z]/i ?

Upvotes: 4

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