CODEWITHSUNDEEP
androidfontslibgdx
BollMose
BollMose

Reputation: 3498

libgdx FreeTypeFontGenerator: how to generate a string with TTF font file correctly?

I use following code to generate font in libgdx: 

class XFont {
    private FreeTypeFontGenerator _generator;    
    public BitmapFont getFont(String str,int size) {
                if (_generator == null) {
                    _generator = new FreeTypeFontGenerator(Gdx.files.internal("win/msyh.ttf"));
                    //_generator = new FreeTypeFontGenerator(Gdx.files.absolute("/system/fonts/DroidSansFallback.ttf"));
                    Gdx.app.log(TAG, "generator"+_generator.toString());
                }

                return _generator.generateFont(size, str, false);
            }
    }

when I call :

XFont x = new XFront();
x.getFont("iiiis",11);

raise exception:

java.lang.RuntimeException: Key with name 'i' is already in map.

I work with chinese and japanese.

Upvotes: 1

Views: 1588

Answers (2)

phucvin
phucvin

Reputation: 73

First, _generator.generateFont(size, str, false) take str as a string that contains all unique characters that you want to generate bitmap font. I preferred use charset for this. Then you should generate a bitmap font just once. Example:

// in your constants
public static final String FONT_CHARSET = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ 1234567890,./;'[]\\`~!@#$%^&*()_+{}|:\"<>?";    

// in your resource loading code
FreeTypeFontGenerator fontGenerator = new FreeTypeFontGenerator(Gdx.files.internal("myFont.ttf"));
BitmapFont myFont = fontGenerator.generateFont(24, FONT_CHARSET, false);
fontGenerator.dipose(); // remember to dispose the generator after used

The FONT_CHARSET contains all characters in the keyboard, I think it is enough for English texts.

Upvotes: 0

nEx.Software
nEx.Software

Reputation: 6862

The generateFont() method takes a string containing the unique characters you'd like to be in the generated font. You then use that generated font to draw a string containing those characters - via font.draw(batch, string, x, y).

Note: I'd recommend not generating a new BitmapFont every time you want to draw a String, but instead generate a font with all the characters you will likely use then reuse that BitmapFont.

Upvotes: 1

Related Questions