Reputation:
In Python 3.3.3, i create a thread to listen some connection to the socket.It likes this:
import threading
import socket
import time
Host = ''
Port = 50000
flag = False
class ServerThread(threading.Thread):
def __init__(self):
threading.Thread.__init__(self)
self._sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
def run(self):
try:
self._sock.bind((Host, Port))
self._sock.listen(5)
while True:
conn, addr = self._sock.accept()
print('Connected by', addr)
except socket.error as msg:
print(msg)
except Exception as e:
print(str(e))
finally:
self._sock.close()
def exit(self):
self._sock.close()
def TargetFunc(vlock):
vlock.acquire()
flag = True
vlock.release()
def main():
sthread = ServerThread()
sthread.start()
vlock = threading.Lock()
time.sleep(10)
vthread = threading.Thread(target = TargetFunc, args = (vlock, ))
vthread.start()
while True:
vlock.acquire()
if flag:
sthread.exit()
vlock.release()
break
vlock.release()
sthread.join()
vthread.join()
if __name__ == '__main__':
main()
There are two threads, one is listening socket, the other is to set a flag. When the flag is True, close the socket, then raise a socket error and catch it, so the listening socket terminates.But why it does not work this.
Thanks!
Upvotes: 1
Views: 514
Reputation: 11968
self._sock.accept()
is blocking. So it will wait until somebody connects. You should use a nonblocking variant (or blocking but with a time-out). So that you can check the exit conditions.
Alternatively you could force an exception in the ServerThread.
Upvotes: 3