CODEWITHSUNDEEP
javaxmlspringspring-mvc
NickJ
NickJ

Reputation: 9559

Spring MVC XML view

I have been following a tutorial here

As it stands, it works fine.

But if I try to convert a class hierarchy to XML, I get exceptions

Example:

@XmlRootElement(name = "stuff")
public class Stuff {

    @XmlMixed
    public List<Other> getList(){
      return records;
    }

}

Other class:

@XmlRootElement(name="other")
public class Other {
  @XmlAttribute int foo;
}

And the important part of the exception:

class mypackage.Other nor any of its super class is known to this context.

Upvotes: 0

Views: 148

Answers (1)

Santosh Joshi
Santosh Joshi

Reputation: 3320

here's a quick workaround:

Add :

@XmlSeeAlso(Other.class) to Stuff .

You should check the following posts for more insights

javax.xml.bind.JAXBException: Class *** nor any of its super class is known to this context

JAXB Exception: Class not known to this context

Upvotes: 1

Related Questions