CODEWITHSUNDEEP
phplaravellaravel-4
WebDevB
WebDevB

Reputation: 492

Laravel 4 Form Post

Im currently in the process of learning Laravel 4.

I'm trying to create a really simple post form, here is my code for the opening of the form:

{{ Form::open(array('post' => 'NewQuoteController@quote')) }}

And then within my NewQuoteController i have the following:

public function quote() {

   $name = Input::post('ent_mileage');
   return $name;

}

I keep getting the following error:

Symfony \ Component \ HttpKernel \ Exception \ NotFoundHttpException

It's probably something really stupid... Thanks.

EDIT

This is what I have in my routes.php

Route::get('/newquote','NewQuoteController@vehicledetails');

Route::post('/newquote/quote', 'NewQuoteController@quote');

Upvotes: 3

Views: 18911

Answers (2)

Antonio Carlos Ribeiro
Antonio Carlos Ribeiro

Reputation: 87719

For POST looks like you need to change it to:

{{ Form::open(array('action' => 'NewQuoteController@quote')) }}

And you need to have a route to your controller action:

Route::post('quote', 'NewQuoteController@quote');

Default method for Form::open() is POST, but if you need to change it to PUT, for example, you will have to 

{{ Form::open(array('method' => 'PUT', 'action' => 'NewQuoteController@quote')) }}

And you'll have to create a new route for it too:

Route::put('quote', 'NewQuoteController@quote');

You also have to chage

$name = Input::post('ent_mileage');

to 

$name = Input::get('ent_mileage');

You can use the same url for the different methods and actions:

Route::get('/newquote','NewQuoteController@vehicledetails');

Route::post('/newquote', 'NewQuoteController@quote');

Route::put('/newquote', 'NewQuoteController@quoteUpdate');

Upvotes: 9

David Donovan
David Donovan

Reputation: 11

Have you tried changing your form open to

{{Form::open(['method'=>'POST', 'route' =>'NewQuoteController@quote')}}

and in your controller access the form input using one of the Input methods ? 

public function quote() {

    $name = Input::get('ent_mileage');

    return $name; 
}

Upvotes: 1

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