Reputation: 219
How to remove duplicate element from Tcl list say:
list is like [this,that,when,what,when,how]
I have Googled and have found lsort unique
but same is not working for me. I want to remove when from list.
Upvotes: 5
Views: 38336
Reputation: 223
Another way, if do not wanna use native lsort function.This is what the interviewer asks :)
`set a "this that when what when how"
for {set i 0} {$i < [llength $a]} {incr i} {
set indices [lsearch -all $a [lindex $a $i]]
foreach index $indices {
if {$index != $i} {
set a [lreplace $a $index $index]
}
}
}
`
Upvotes: 0
Reputation: 107
glenn jackman's answer work perfectly on Tcl 8.6 and above.
For Tcl 8.4 and below (No dict command). You can use:
proc list_unique {list} {
array set included_arr [list]
set unique_list [list]
foreach item $list {
if { ![info exists included_arr($item)] } {
set included_arr($item) ""
lappend unique_list $item
}
}
unset included_arr
return $unique_list
}
set list [list this that when what when how]
set unique [list_unique $list]
This will also preserve the order of the elements and this is the result:
this that when what how
Upvotes: 1
Reputation: 246774
You could also use an dictionary, where the keys must be unique:
set l {this that when what when how}
foreach element $l {dict set tmp $element 1}
set unique [dict keys $tmp]
puts $unique
this that when what how
That will preserve the order of the elements.
Upvotes: 9
Reputation: 181
The following works for me
set myList [list this that when what when how]
lsort -unique $myList
this returns
how that this what when
which you could store in a new list
set uniqueList [lsort -unique $myList]
Upvotes: 13