CODEWITHSUNDEEP
pythonrandom
Eric Cuevas
Eric Cuevas

Reputation: 63

Printing out a random string (Python)

I am asked to produce a random string using a previously defined value.

THREE_CHOICES = 'ABC'
FOUR_CHOICES = 'ABCD'
FIVE_CHOICES = 'ABCDE'

import random

def generate_answers(n: int) -> str:
    '''Generates random answers from number inputted '''
    for i in range(0,n):
        return random.choice(FOUR_CHOICES)
        continue

What I am trying to get happening here is, if I were to plug in 7 into the function I'd get something like "ABDCBBA"

A random 7 character string from the specified letters. However, this code is returning only one random character no matter what number I put in (has to be non-zero).

I don't know what to do here, can someone point me in the right direction?

Upvotes: 0

Views: 172

Answers (2)

Serial
Serial

Reputation: 8045

you could just return a list like this:

def generate_answers(n):
    '''Generates random answers from number inputted '''
    randoms = [random.choice(FOUR_CHOICES) for _ in range(0,n)]
    return randoms
    #return ''.join(randoms) to get string

print generate_answers(7)

this would print a list like this: ['D', 'D', 'D', 'B', 'A', 'A', 'C']

you could join the list if you want a string

Upvotes: 1

Jules Gagnon-Marchand
Jules Gagnon-Marchand

Reputation: 3781

not tested, but should work.

THREE_CHOICES = 'ABC'
FOUR_CHOICES = 'ABCD'
FIVE_CHOICES = 'ABCDE'

import random

def generate_answers(n):
    '''Generates random answers from number inputted '''
    answerList = ""
    for i in range(0,n):
        answerList += random.choice(FOUR_CHOICES)
    return answerList

Upvotes: 0

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