Eric Salemi
Eric Salemi

Reputation: 129

Matlab: Behavior of the unique function

I'm currently migrating code from R2012a to R2013b.

I noticed that the unique function behavior has changed:

R2012a

>> size(unique([]))

ans =

     0     0

R2013b

>> size(unique([]))

ans =

     0     1

It seems counter-intuitive to me that a 0x0 matrix would become a 0x1 matrix after removing doublons, which is essentially what the unique function does. Does anybody has a rationale for this?

Upvotes: 6

Views: 647

Answers (2)

Dennis Jaheruddin
Dennis Jaheruddin

Reputation: 21561

I don't know whether this is the reason, but it does come with an advantage.

Now you will see that unique(M) gives the same output as unique(M(:)), even if M is empty.

Example:

M = magic(5);
isequal(size(unique(M)), size(unique(M(:)))); 
M = [];
isequal(size(unique(M)), size(unique(M(:)))); 

The latter returns false on old versions of matlab, this may be confusing.

Upvotes: 1

Daniel
Daniel

Reputation: 36720

The behaviour has changed with R2013a, if you need the old behaviour use:

size(unique([],'legacy'))

If you need code for both versions, I would recommend to write some function which calls unique(x,'legacy') for new versions and unique(x) for old versions.

btw: same issue with union, intersect, setdiff, setxor and ismember

Upvotes: 7

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