Reputation: 129
I'm currently migrating code from R2012a to R2013b.
I noticed that the unique
function behavior has changed:
R2012a
>> size(unique([]))
ans =
0 0
R2013b
>> size(unique([]))
ans =
0 1
It seems counter-intuitive to me that a 0x0 matrix would become a 0x1 matrix after removing doublons, which is essentially what the unique function does. Does anybody has a rationale for this?
Upvotes: 6
Views: 647
Reputation: 21561
I don't know whether this is the reason, but it does come with an advantage.
Now you will see that unique(M)
gives the same output as unique(M(:))
, even if M
is empty.
Example:
M = magic(5);
isequal(size(unique(M)), size(unique(M(:))));
M = [];
isequal(size(unique(M)), size(unique(M(:))));
The latter returns false on old versions of matlab, this may be confusing.
Upvotes: 1
Reputation: 36720
The behaviour has changed with R2013a, if you need the old behaviour use:
size(unique([],'legacy'))
If you need code for both versions, I would recommend to write some function which calls unique(x,'legacy')
for new versions and unique(x)
for old versions.
btw: same issue with union
, intersect
, setdiff
, setxor
and ismember
Upvotes: 7