Reputation: 467
I'm playing around with CompletableFuture and streams in Java 8 and I get different printouts each time I run this. Just curious, why?
public class DoIt {
public static class My {
private long cur = 0;
public long next() {
return cur++;
}
}
public static long add() {
long sum = 0;
for (long i=0; i<=100;i++) {
sum += i;
}
return sum;
}
public static long getResult(CompletableFuture<Long> f) {
long l = 0;
try {
f.complete(42l);
l = f.get();
System.out.println(l);
} catch (Exception e) {
//...
}
return l;
}
public static void main(String[] args){
ExecutorService exec = Executors.newFixedThreadPool(2);
My my = new My();
long sum = Stream.generate(my::next).limit(20000).
map(x -> CompletableFuture.supplyAsync(()-> add(), exec)).
mapToLong(f->getResult(f)).sum();
System.out.println(sum);
exec.shutdown();
}
}
If I skip the f.complete(42l) call I always get the same result.
Upvotes: 1
Views: 119
Reputation: 1727
http://download.java.net/jdk8/docs/api/java/util/concurrent/CompletableFuture.html#complete-T-
by the time the complete(42l)
call happens, some add()
's may have already completed.
Upvotes: 1