CODEWITHSUNDEEP
linuxbashcommand-lineterminal
Villi Magg
Villi Magg

Reputation: 1193

How to compress multiple folders, each into its own zip archive?

So I want to create a script that enables me to compresses each folder into its own zip archive and not into a one big zip file.

As an example, I've got a directory:

+ MyDirectory/
| |
| + Folder_01/
| |
| + Folder_02/
| |
| + Folder_03/
|

When I'm done running the script under MyDirectory then I would have a zip file of each Folder which is inside MyDirectory: Folder_01.zip, Folder_02.zip and Folder_03.zip. I know some BASH but this is something I can't figure out.

How can this be done?

Kind regards.

Upvotes: 46

Views: 33802

Answers (5)

Crystalline
Crystalline

Reputation: 29

I personally use

fd . -t d -x zip -r '{}.zip' '{}'

(fd might be fd-find depending on your OS)

Upvotes: 0

Ahmed Bermawy
Ahmed Bermawy

Reputation: 2530

I take the old solutions and get back with another good solution that works for any directory in any place in you drive

This code in Bash

#!/bin/bash

folderPath=/home/ahmed/test/

for folder in $folderPath*
do
        folderName=$(basename $folder)
        cd $folderPath && zip -r $folderName.zip $folderName
done

So all folders inside test folder will be zipped in the same folder

Upvotes: 0

ahmed zeaad
ahmed zeaad

Reputation: 183

here 

for i in */; do tar -czvf "${i%/}.tar.gz" "$i"; done

Upvotes: 13

Gajus
Gajus

Reputation: 73738

Consider using xz algorithm if you require smaller output (at the cost of longer process):

for d in */ ; do
    outName=$d;
    outName=${outName// /\-};
    outName=${outName//[!0-9a-z-]};
    dirName=$d;
    dirName=${dirName//\/}
    tar -c "$dirName" | xz -e > $outName.tar.xz
done

This code will sanitise folder names and produce .tar.xz for every folder in the current directory.

Upvotes: 1

Igor Chubin
Igor Chubin

Reputation: 64563

for i in *
do
[ -d "$i" ] && zip -r "$i.zip" "$i"
done

You walk through all the directories and create zip for each of them.

Or even more concise:

for i in */; do zip -r "${i%/}.zip" "$i"; done

(thanks to damienfrancois for suggestion).

Upvotes: 82

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