CODEWITHSUNDEEP
pythoncryptographypycryptom2crypto
Zelid
Zelid

Reputation: 7195

How to make M2Crypto work with aes128-cbc-pkcs7?

In Python script I need to decrypt data encrypted by aes128-cbc-pkcs7

I checked example in Problem with M2Crypto's AES answer, but it describes aes128-cbc and I have no idea how to adopt it for aes128-cbc-pkcs7

All I have is a key:

key = 'MIGeMA0GCSqGSIb3DQEBAQUAA4GMADCBiAKBgHdH2zoKQJ43olhVZstEiBHjZvhUkGL1YcB2baSlHsHjoV5uRkYDyPEHUaN7htski3aGoIUY1vEF7nv0dJaM686KqEfkIxzlRizdnNJr+A8j1OOnOPOooqTuf06570kEEqXCW2STlLIMxwIESPHXAqiKYMPUtNGfu+PpmdY6NUHDAgMBAAE='

or

    key = """MIGeMA0GCSqGSIb3DQEBAQUAA4GMADCBiAKBgHdH2zoKQJ43olhVZstEiBHjZvhU
kGL1YcB2baSlHsHjoV5uRkYDyPEHUaN7htski3aGoIUY1vEF7nv0dJaM686KqEfk
IxzlRizdnNJr+A8j1OOnOPOooqTuf06570kEEqXCW2STlLIMxwIESPHXAqiKYMPU
tNGfu+PpmdY6NUHDAgMBAAE="""

I'm not sure how to store the key in a right way - with line brakes or without.

Can you please provide some example how to use aes128-cbc-pkcs7 to encode/decode that should be similar to aes128-cbc (explained in Problem with M2Crypto's AES)

Sorry if questions sounds strange, I'm total newbie in cryptography.

Upvotes: 0

Views: 876

Answers (1)

Maarten Bodewes
Maarten Bodewes

Reputation: 93948

You cannot use encrypt using just AES if you've been given an RSA public key. You need to use hybrid encryption: generate a random AES key of 16, 24 or 32 bytes, then encrypt. You can keep to a zero IV if you generate a new AES key for each encryption.

The AES key itself can then be encrypted using the public key you've been given, using either OAEP or - for backwards compatibility - PKCS#1 v1.5 padding.

The default module does not seem to use padding, if I read the documentation correctly. I've found a padding/unpadding routine on pastebin, thanks go to Peter for sharing:

def pkcs7_pad(data, blocksize=16):
    padlen = blocksize - len(data) % blocksize
    return data + bytes([padlen]) * padlen


def pkcs7_unpad(data, blocksize=16):
    if data:
        padlen = data[-1]
        if 0 < padlen < blocksize:
            if data.endswith(bytes([padlen]) * padlen):
                return data[:-padlen]

    raise ValueError('incorrect padding')

Note that just encryption is not secure if you are using this over a communication channel. It is required to add a message authentication code (MAC), even if you just require confidentiality of the plaintext. Incorrect use of CBC mode encryption may make the protocol vulnerable to padding oracle attacks.

Upvotes: 2

Related Questions