CODEWITHSUNDEEP
renamezshbatch-rename
jO.
jO.

Reputation: 3512

replacing filenames with parent folder name without changing file endings

Im struggling replacing filenames with parent folder name and conserving the different file endings.

Example;

.sp1/4287/4287/iho.cst
.sp1/4287/4287/iho.dbf
.sp1/4287/4287/iho.prj
.sp1/4287/4287/iho.shp
.sp1/4287/4287/iho.shx

renamed to;

.sp1/4287/4287/4287.cst
.sp1/4287/4287/4287.dbf
        .
        .
        .

Im currently trying out zsh shell using zmv. 

zmv '(*)/*' '$1/$1'

But this is matching all. I don't get how to escape the file endings (if possible). Also tried rename but without success.

Since I have multiple sp folders (sp2, sp3, ..spN) and since each e.g. sp1/ contain a lot of subfolders like 4287 with the same type of files, Im seeking a batch solution.

Any pointers would be appreciated.

UPDATE

This works when in spN/XXXX/;

zmv '(*)/*.(*)' '$1/$1.$2';

How can I write a loop going through the spN/XXXX/ folders and executing the above zmv code? 

#!/usr/bin/env zsh
source ~/.zshrc

for i in ./*;
  for y in i;
    do
      zmv '(*)/*.(*)' '$1/$1.$2';
    done

Upvotes: 2

Views: 396

Answers (2)

rendon
rendon

Reputation: 2363

I don't know zmv but try this script:

while read file
do
    prefix=$(echo $file | sed 's|\(.*\)/.*$|\1|');
    parent=$(echo $file | sed 's|.*/\([^/]\+\)/[^/]\+$|\1|');
    child=$(echo $file | sed 's|.*/\([^.]\+\).*$|\1|');
    ext=$(echo $file | sed 's|.*/[^.]\+\.\(.\+\)$|\1|');
    mv "$prefix/$child.$ext" "$prefix/$parent.$ext"
done < <(find -type f)

EDIT: The first version doesn't work if the files or directories contains spaces.

Upvotes: 0

Barmar
Barmar

Reputation: 780899

I'm not really familiar with zmv, but I guess this will do it:

zmv '(*)/*.(*)' '$1/$1.$2'

Upvotes: 1

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