CODEWITHSUNDEEP
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Dreadlord
Dreadlord

Reputation: 413

Wordpress PHP - replace string with string

So im using Wordpress advanced custom fields, outpit is this:

<?php the_field('output'); ?>

Output is pure text, it can be: one, two or three. I need to replace output text with image.

I tried this example: if string... but its not working for me. I also tried swithc example on the bottom of that link but still not working. Probobly couse they use litlle bit diferent output. Can someone help me?

Upvotes: 0

Views: 503

Answers (4)

David Gard
David Gard

Reputation: 12047

I don't use Advanced Custom Fields, but if it has no equivalent get function for the_field() (which would surprise me), then you could use the following method (obviously filling in the src and alt attributes as required).

<?php
ob_start();
the_field('output');
$result = ob_get_clean();

switch($result) :

    case 'one' :
        echo '<img src="" alt="" />';
        break;
    case 'two' :
        echo '<img src="" alt="" />';
        break;
    case 'three' :
        echo '<img src="" alt="" />';
        break;

endswitch;
?>

Upvotes: 0

Martin Bean
Martin Bean

Reputation: 39389

From what I understand about WordPress, functions like the_title() and the_content() just echo the content out directly, but usually have a corresponding get_the_* function that returns the value instead. the_field() has get_field(). So you can capture it in a variable and use it in a switch statement:

<?php
$output = get_field('output');

switch ($output) {
    case 'one':
        // first image
    break;
    case 'two':
        // second image
    break;
    case 'three':
        // third image
    break;
}

Upvotes: -2

bitWorking
bitWorking

Reputation: 12665

You'd better use a select field because you cannot force the users to add specific values with a textfield.

http://www.advancedcustomfields.com/resources/field-types/select/

And than do it like user574632's answer.

Upvotes: 0

Steve
Steve

Reputation: 20469

You need to use get_field() rather that the_field().

As per your linked question:

    $items = array(
    "one" => "one.png",
    "two" => "two.png",
    "three" => "three.png"
);


<img src="<?php echo $items[ get_field('output') ]; ?>" />

Upvotes: 4

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