Reputation: 96837
Consider the following code:
for(int i = 0;i < 200;i++)
{
ArrayList<Integer> currentList = new ArrayList<Integer>() {{
add(i);
}};
// do something with currentList
}
currentList
? I'm just curious :)
Upvotes: 11
Views: 2437
Reputation: 59299
The compiler is going to transform any anonymous class to a named inner class. So your code, will be transformed to something along the lines of:
class OuterClass$1 extends ArrayList<Integer> {
OuterClass$1(int i) {
super();
add(i);
}
}
for (int i = 0; i < 200; i++) {
ArrayList<Integer> currentList = new OuterClass$1(i);
}
Upvotes: 16
Reputation: 403501
ArrayList<Integer> currentList = new ArrayList<Integer>() {{
add(i);
}};
is creating a new instance of the anonymous class each time through your loop, it's not redefining or reloading the class every time. The class is defined once (at compile time), and loaded once (at runtime).
There is no significant performance hit from using anonymous classes.
Upvotes: 15