CODEWITHSUNDEEP
ajaxnode.jsexpressroutes
Erik
Erik

Reputation: 14750

How to make middleware for response on all ajax requests

I need to make a single middleware that will handle each response to web user. I try to make something like the following:

function ajaxResponseMiddleware(req, res, next) {
   var code = res.locals._code || 200;
   var data = res.locals._response;

   res.json(code, data);
}

app.get('/ajax1', function(req, res, next){

    // Do something and add data to be responsed
    res.locals._response = {test: "data2"};

    // Go to the next middleware 
    next();

}, ajaxResponseMiddleware);


app.get('/ajax2', function(req, res, next){

    // Do something and add data to be responsed
    res.locals._response = {test: "data2"};
    res.locals._code = 200;

    // Go to the next middleware 
    next();

}, ajaxResponseMiddleware);

The response is handled in ajaxResponseMiddleware function where I can add some default state for all my ajax responses.

One thing that I don't like in the approach above is the adding ajaxResponseMiddleware function in each route.

So what do you think about this approach? May you advise improvements or share your experience.

Upvotes: 2

Views: 1817

Answers (1)

damphat
damphat

Reputation: 18956

middleware is just a function function (req, res, next) {}

var express = require('express');
var app = express();

// this is the middleware, you can separate to new js file if you want
function jsonMiddleware(req, res, next) {
    res.json_v2 = function (code, data) {
        if(!data) {
            data = code;
            code = 200;
        }
        // place your modification code here
        //
        //
        res.json(code, data)
    }
    next();
}

app.use(jsonMiddleware); // Note: this should above app.use(app.router)
app.use(app.router);

app.get('/ajax1', function (req, res) {
    res.json_v2({
        name: 'ajax1'
    })
});

app.listen(3000);

Upvotes: 5

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