Reputation: 1829
On my wicket page I have a link that opens a second page in another tab/new window.
<a href="/MySecondPage" target="_blank">Click here for second window</a>
These windows are meant to be used in parallel (e.g. in a two-monitor-environment). But I don't want to spread out different menu entries over both screens, so I want all menu entries to stay on MyFirstPage
, even if they should influence MySecondPage
only.
My ultimate goal is to click a menu entry on MyFirstPage
that results in displaying a new Component
on MySecondPage
. Is this even possible? How can I obtain a java-reference of MySecondPage
inside MyFirstPage
or establish some other sort of communication?
Everything I found while researching only applied to modal windows or Wicket 1.4, but MySecondPage
is not modal.
Upvotes: 1
Views: 1020
Reputation: 2906
There is WebSocket support in Wicket 6: http://wicketinaction.com/2012/07/wicket-6-native-websockets/
Basically you need to add WebSocketBehavior
to the page to make it available for messages from the server.
On the other hand, you can send messages to the server via Wicket.WebSocket.send("A message sent by the client");
I have never tired it but it sounds very promising.
Upvotes: 0
Reputation: 16131
Maybe wicket's event bus is an option, see: http://code.google.com/p/wicket-guide/downloads/list - Chapter 15.3 Wicket events infrastructure
You could send the event in MyFirstPage
, receive it in your Session
or Application
and there send it to MySecondPage
. Session
and Application
implement IEventSink
: http://ci.apache.org/projects/wicket/apidocs/6.x/org/apache/wicket/event/IEventSink.html
Upvotes: 3