CODEWITHSUNDEEP
c#javalistarraylist
Peterdk
Peterdk

Reputation: 16015

C# => JAVA: Filling a static ArrayList on declaration. Possible?

In my C# project I have a static List that gets filled immediately when declared.

  private static List<String> inputs = new List<String>()
        { "Foo", "Bar", "Foo2", "Bar2"};

How would I do this in Java using the ArrayList?

I need to be able to access the values without creating a instance of the class. Is it possible?

Upvotes: 2

Views: 12700

Answers (5)

Jason Nichols
Jason Nichols

Reputation: 11733

You can make static calls by enclosing them within static{} brackets like such:

private static final List<String> inputs = new ArrayList<String>();

static {
  inputs.add("Foo");
  inputs.add("Bar");
  inputs.add("Foo2");
  inputs.add("Bar2");
}

Upvotes: 7

Kevin Bourrillion
Kevin Bourrillion

Reputation: 40851

You may enjoy ImmutableList from Guava:

ImmutableList<String> inputs = ImmutableList.of("Foo", "Bar", "Foo2", "Bar2");

The first half of this youtube video discusses the immutable collections in great detail.

Upvotes: 3

Clint
Clint

Reputation: 9058

You can use Double Brace Initialization. It looks like:

private static List<String> inputs = new ArrayList<String>()
  {{ add("Foo");
    add("Bar");
    add("Foo2");
    add("Bar2");
  }};

Upvotes: 16

MAK
MAK

Reputation: 26586

I don't understand what you mean by

able to access the values without creating a instance of the class

but the following snippet of code in Java has pretty much the same effect in Java as yours:

private static List<String> inputs = Arrays.asList("Foo", "Bar", "Foo2", "Bar2");

Upvotes: 8

jdmichal
jdmichal

Reputation: 11162

Do you need this to be an ArrayList specifically, or just a list?

Former:

private static java.util.List<String> inputs = new java.util.ArrayList<String>(
    java.util.Arrays.<String>asList("Foo", "Bar", "Foo2", "Bar2"));

Latter:

private static java.util.List<String> inputs =
    java.util.Arrays.<String>asList("Foo", "Bar", "Foo2", "Bar2");

java.util.Arrays#asList(...) API

Upvotes: 5

Related Questions