Reputation: 18220
I can't for the life of me figure out how you would do the following:
$("select").change(function() {
var cb = $(this).parent().next().find("input[type=checkbox]");
$(this).val().length > 0 ? cb.attr('checked', true) : cb.attr('checked', false)
});
$("input[type=text]").keyup(function() {
var cb = $(this).parent().next().find("input[type=checkbox]");
$(this).val().length > 0 ? cb.attr('checked', true) : cb.attr('checked', false)
});
As one function. Really don't like repetition, especially when they're doing the exact same thing.
My jQuery jedi skills aren't tailored to this scenario.
Upvotes: 0
Views: 337
Reputation: 129812
You first declare the function:
function myFunc() {
var cb = ...
}
and then add the assignments:
$('select').change(myFunc);
$('input[type=text]').keyup(myFunc);
Upvotes: 2