CODEWITHSUNDEEP
c#asp.net-mvcweb-servicesexceptionsoap
gog
gog

Reputation: 12988

Throw exception in ActionResult method

I have a view with a upload controller wich fires this ActionResult:

    [HttpPost]
    public ActionResult ProcessSubmitUpload(HttpPostedFileBase attachments, Guid? idDocument)
    {
          //Validations
          var xmlDocument = XDocument.Load(attachments.InputStream);
          DocumentCommonHelper.SendFile(xmlDocument);
    }

The SendFile method:

  public static void SendCte(XDocument xmlDocument)
  {
       var client = new WsSoapClient();
       client.InsertXML(xmlDocument);
  }

The webservice returns SoapException if somethig goes wrong, like: "The IDDocument does not exist" , etc etc.

But in MVC when im debugging if something goes wrong in the InsertXml method i cannot catch it, the debug navigation just stop and throw a Upload File error.

I would like to catch the return message of the InsertXML method in my action e return it to my view. Like a 'alert' popup. How can i do that?

Upvotes: 2

Views: 3204

Answers (2)

Paul Taylor
Paul Taylor

Reputation: 5751

You can return the error message to the view in the ModelState object. The view can display it using a ValidationSummary helper:

[HttpPost]
public ActionResult ProcessSubmitUpload(HttpPostedFileBase attachments, Guid? idDocument)
{
      //Validations
      var xmlDocument = XDocument.Load(attachments.InputStream);
      try
      {
          DocumentCommonHelper.SendFile(xmlDocument);
      }
      catch(Exception ex)
      {
          ModelState.AddModelError("ProcessSubmitUpload", ex.Message);
          return View(new MyViewModel())
      }
}

View:

@using(Html.BeginForm("ProcessSubmitUpload", "MyController", FormMethod.Post))
{
    @Html.ValidationSummary()
    ... etc.
}

Upvotes: 3

Oleksandr Kobylianskyi
Oleksandr Kobylianskyi

Reputation: 3380

You can wrap your SendFile method call with try..catch block and it catch section fill return result with appropriate information about fault.

Upvotes: 2

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