What's the difference between 'isset()' and '!empty()' in PHP?

Question

I don't understand the difference between isset() and !empty().

Because if a variable has been set, isn't it the same as not being empty?

Answer 1

ISSET checks the variable to see if it has been set. In other words, it checks to see if the variable is any value except NULL or not assigned a value. ISSET returns TRUE if the variable exists and has a value other than NULL. That means variables assigned a "", 0, "0", or FALSE are set, and therefore are TRUE for ISSET.

EMPTY checks to see if a variable is empty. Empty is interpreted as: "" (an empty string), 0 (integer), 0.0 (float)`, "0" (string), NULL, FALSE, array() (an empty array), and "$var;" (a variable declared, but without a value in a class.

Answer 2

And one more remark. empty() checks if the variable exists as well. I.e. if we perform empty() to the variable that wasn't declared, we don't receive an error, empty() returns 'true'. Therefore we may avoid isset() if next we need to check if the variable empty.

So

isset($var) && !empty($var)

will be equals to

!empty($var)

Answer 3

Source :http://php.net/manual/en/types.comparisons.phpThis page shows the comparison of the empty(),is_null(),isset().

Answer 4

The type comparison tables gives answer of all question about these operators

http://php.net/manual/en/types.comparisons.php